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AP Computer Science 1.5 Standard Data Structures 174 Views
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Description:
AP Computer Science 1.5 Standard Data Structures. Which of the following is a correct iterative implementation?
Transcript
- 00:00
Thank you We sneak And here's your shmoop twos you're
- 00:05
brought to you by the power of two dirt bikes
- 00:10
now close All right which of the following is a
- 00:12
correct iterated implementations right here your potential answers And why
- 00:19
would i miss you Power raise candy bar Okay well
Full Transcript
- 00:26
there are a number of ways to populate an array
- 00:29
and the two most obvious are sequential and iterated implementations
- 00:33
Well sequential is exactly as it sounds going right down
- 00:36
the line manually giving values to each array element one
- 00:39
by one that's what's happening in answer e And because
- 00:43
we're in the market for an illiterate of solution rather
- 00:45
than sequential we can throw e out right away because
- 00:49
the values we're going to be filling the array with
- 00:52
are all mathematically related powers of two which are practically
- 00:56
blood relatives or like a really close biker gang we
- 00:59
could pretty easily is an illiterate of implementation Here We'll
- 01:03
just need a simple loop that travels down the array
- 01:05
via its indices and at each stop multiplies have value
- 01:09
by two and copies that product to the array before
- 01:12
moving on Well let's see if any of the remaining
- 01:14
loops fit the bill Option a looks good Really good
- 01:18
Luke runs without errors but it doesn't do right in
- 01:21
terms of the problem given which is to fill the
- 01:24
array with the first ten powers of two starting with
- 01:26
two So this option starts with one instead All right
- 01:30
Well in fact he has the same problem By the
- 01:34
way b is an interesting luke but makes a textbook
- 01:36
mistake on the very first line It fails to take
- 01:39
into account the old array index begins at zero thing
- 01:43
The energy er i being used as an inter reiter
- 01:46
should started zero because in a raise indexing scheme starts
- 01:50
at zero not one run This bit of code and
- 01:53
index zero would get skipped over So no good but
- 01:56
just leave c which is our answer It heroically starts
- 01:59
it's iterated zero and the first value power at two
- 02:04
While eyes less than the total length of the array
- 02:06
it'll go through loop that changes the current array element
- 02:09
to the value of power Cia network Change the value
- 02:13
of power to be itself times two and increases the
- 02:16
value of the it aerator by one and that's the
- 02:18
whole hot well
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