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Intermediate Algebra Videos 25 videos
ACT Math: Intermediate Algebra Drill 4, Problem 2. What is the root of this equation?
ACT Math Intermediate Algebra Drill 1, Problem 3. Can you find the value of a in this expression?
ACT Math Intermediate Algebra Drill 2, Problem 2. How else can the expression be written?
ACT Math 3.2 Intermediate Algebra 320 Views
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Description:
ACT Math: Intermediate Algebra Drill 3, Problem 2. Find the sixth number in the series.
Transcript
- 00:02
And we're gettin' shmoopy with it...
- 00:05
Find the 6th number: 1, 3, 9, 27, something, something.
- 00:12
And here are the potential answers...
- 00:15
OK so what is this question asking?
- 00:18
Another geometric pattern; each number is simply 3 times the previous number in the sequence.
Full Transcript
- 00:27
But note, they are trying to be sneaky here.
- 00:30
They don't want the next number in the sequence they want the SIXTH one. So we need to find
- 00:35
the next TWO
- 00:36
We have 27 times 3 which gets us 81
- 00:39
then multiply 3 again to get the 6th number in the series, which is 243.
- 00:44
Answer: E.
- 00:46
Nice try, math problem.
- 00:47
You have to get up a little earlier in the morning to pull the wool over OUR eyes.
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