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Description:
AP Chem 1.3 Laws of Thermodynamics. How much energy would be required to change the temperature of 200 g of aluminum as described in the video?
Transcript
- 00:04
Here’s your Shmoop du jour, brought to you by aluminum. [Plane in the sky]
- 00:07
From airplane wings to surgical instruments, aluminum is useful in many ways…
- 00:12
…. but soda cans still take the cake for us. [Guy drinking soda on a plane]
- 00:15
Ah.
- 00:16
Refreshing. [Guy chucks the can away]
Full Transcript
- 00:17
Here’s our question:
- 00:18
Aluminum is a metal and a key raw material.
- 00:20
It is used to makes soda cans, foil, and even airplanes.
- 00:24
How much energy would be required to change the temperature of 200.0 g of aluminum from [The question being written out]
- 00:30
10.0 °C to 25.0 °C?
- 00:33
The specific heat of aluminum is 0.902 J/g °C.
- 00:39
And here are the potential answers, alright a bunch of joules [The answers appear]
- 00:44
Alright, lets see (glug, glug, glug) ahhh, seventh can today.
- 00:48
Okay, now that we’re all sufficiently hydrated, let’s get down to defeat the Huns… [Man has his fists up]
- 00:52
…uh. [Guy looks confused]
- 00:53
Sorry, we meant "to defeat this problem."
- 00:55
We're always getting chemistry and Mulan confused. [People in a chemsitry lab]
- 00:58
To solve today’s calorimetry question, we need to use this equation which relates [Teacher writing on a blackboard]
- 01:04
the amount of heat or energy transferred, Q, with a material’s mass, m, heat capacity,
- 01:11
C, and change in temperature, delta T. Phew.
- 01:14
That was a mouthful.
- 01:17
Quick, someone give us an eighth can of soda so we can rehydrate. [Guy drinking another can of soda with a pile of empties behind him]
- 01:19
Ah, much better.
- 01:20
So we’re trying to find Q, the amount of heat or energy transferred into the aluminum [Guy collapses onto the floor]
- 01:24
to heat it up.
- 01:25
From the problem statement, we know that the mass of aluminum that is heated is 200g
- 01:29
We also know that the specific heat is 0.902 joules per gram per degree
- 01:33
Celsius.
- 01:34
Finally, we know the aluminum is heated from 10 °C to 25 °C, which means a change [The equation working is written on the blackboard]
- 01:39
in temperature is 15 °C.
- 01:41
If we multiply this all out, we find that Q is 2,706 joules.
- 01:46
Rounding down to 2,700, this is answer choice (D).
- 01:50
What better way to celebrate our success than with a delicious can of soda? [Guy drinking soda on a plane again]
- 01:52
Ugh, that one was kind of sickening. …and why are our teeth suddenly falling
- 01:56
out? [Guy is crying]
- 01:57
Only one thing to do.
- 01:58
Relax, crack open another can. [Guy smiles and some of his teeth have fallen out]
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